216=(b^2+6b)/2

Solution for 216=(b^2+6b)/2 equation:

216=(b^2+6b)/2

We move all terms to the left:

216-((b^2+6b)/2)=0

We multiply all the terms by the denominator


-((b^2+6b)+216*2)=0


We calculate terms in parentheses: -((b^2+6b)+216*2), so:

(b^2+6b)+216*2

We add all the numbers together, and all the variables

(b^2+6b)+432

We get rid of parentheses

b^2+6b+432

Back to the equation:

-(b^2+6b+432)


We get rid of parentheses

-b^2-6b-432=0

We add all the numbers together, and all the variables

-1b^2-6b-432=0

a = -1; b = -6; c = -432;
Δ = b2-4ac
Δ = -62-4·(-1)·(-432)
Δ = -1692
Delta is less than zero, so there is no solution for the equation